scope - How to access private variable of Python module from class -

in python 3, prefixing class variable makes private mangling name within class. how access module variable within class?

for example, following 2 ways not work:

__a = 3 class b:     def __init__(self):         self.a = __a b = b() 

results in:

traceback (most recent call last):   file "<stdin>", line 1, in <module>   file "<stdin>", line 3, in __init__ nameerror: name '_b__a' not defined 

using global not either:

__a = 3 class b:     def __init__(self):         global __a         self.a = __a b = b() 

results in:

traceback (most recent call last):   file "<stdin>", line 1, in <module>   file "<stdin>", line 4, in __init__ nameerror: name '_b__a' not defined 

running locals() shows variable __a exists unmangled:

>>> locals() {'__package__': none, '__name__': '__main__',  '__loader__': <class '_frozen_importlib.builtinimporter'>,  '__doc__': none, '__a': 3, 'b': <class '__main__.b'>,  '__builtins__': <module 'builtins' (built-in)>, '__spec__': none} 

[newlines added legibility]

running same code in module (as opposed interpreter) results in exact same behavior. using anaconda's python 3.5.1 :: continuum analytics, inc..

it's ugly access globals:

__a = 3 class b:     def __init__(self):         self.a = globals()["__a"] b = b() 

you can put in dict:

__a = 3  d = {"__a": __a}  class b:     def __init__(self):         self.a = d["__a"] b = b() 

or list, tuple etc.. , index:

__a = 3  l = [__a]  class b:     def __init__(self):         self.a = l[0] b = b()