printing - awk: print columns based on values of another column -

i have file 6 columns, , want print first 2 columns of lines have value >3 in sixth column.

this statement prints lines sixth column > 3

awk '$6 > 3' file > out

this statement prints first 2 columns:

awk '{print $1,$2}' file > out

anyone knows how combine these 2 commands one-liner?

you there,just said, "combine them"! . try this:

awk '$6>3{print $1,$2}' file >out

If code