xml - Create hyperlink with concat in XSLT --> HTML -

hi , happy year !

once again, need transformation in xslt.

i have xml-tei file lot of pb elements. instance :

<pb ed="bnf" id="f77.image.r"/> 

i have in same file 1 link element :

<link id="bnf" target="http://test.com:/12148/btv1b90621925/"/> 

my transformation in xslt should not transform <pb> element in html : [77r] [77r] should hyperlink.

now, first stuff :

<xsl:template match="pb[@ed='bnf']"><span class="pb">         <xsl:text> [</xsl:text>         <xsl:value-of select="substring-after(substring-before(@id, '.image.'), 'f')"/><xsl:value-of select="substring-after(@id, '.image.')">         </xsl:value-of>         <xsl:text></xsl:text>             <xsl:apply-templates/>             <xsl:text>] </xsl:text>     </span>     </xsl:template>  

how can reach link element , [f77r] takes value of link , concat id of pb element ? every pb should hyperlink (with end changing each pb) :

http://test.com:/12148/btv1b90621925/f77.image.r

thank :)

best wishes, micha

it looks use key here, link elements there id attribute.

<xsl:key name="links" match="link" use="@id" /> 

then can use key target of link when construct href hyperlink

<a href="{key('links', @ed)/@target}{@id}"> 

note double-use of attribute value templates create attribute. write if wanted

<a href="{concat(key('links', @ed)/@target, @id)}"> 

try xslt template

<xsl:template match="pb[@ed='bnf']">     <span class="pb">         <a href="{concat(key('links', @ed)/@target, @id)}">             <xsl:text> [</xsl:text>             <xsl:value-of select="substring-after(substring-before(@id, '.image.'), 'f')"/><xsl:value-of select="substring-after(@id, '.image.')">             </xsl:value-of>             <xsl:apply-templates/>             <xsl:text>] </xsl:text>         </a>     </span> </xsl:template>  

this should output following:

<span class="pb">     <a href="http://test.com:/12148/btv1b90621925/f77.image.r"> [77r] </a> </span>